Need Some more Math Help(new problems added)

WakeOfAshes

Rochester Institute of Technology. Working on a Masters in EE with an emphasis on Digital Signal Processing. I'm only going part time though, 1 class per quarter. Should be done in about 2 years.

JLRedWing13

That was a division sign? I thought it was a plus, which is what made me confused. <_>

WakeOfAshes

yeah I thought plus sign as well which didnt reduce to anything... however if it is division then it makes sense and reduced to A.

Adam

then cancel like terms

= 10*(y^5)
---------
x^3

there are no like terms for this one is there.

JLRedWing13

yeah I thought plus sign as well which didnt reduce to anything... however if it is division then it makes sense and reduced to A.

I didn't think anyone used that division sign anymore.....

WakeOfAshes

then cancel like terms

= 10*(y^5)
---------
x^3

there are no like terms for this one is there.

No because it all either Mult or divide. The "like" terms in this case are just X and Y. If it helps you think of things, try rewriting things like this


15*(12x(y^6) )
--------------
9x*(2x^3)*y

=
180 * x * y *y * y *y *y
-------------------
18 * x *x *x *x *y

then it makes it clear that you can just cancel out that one x in the numerator with one in the denom. and the same thing with the y so then it equals


10*(y^5)
---------
x^3

WakeOfAshes

make sense?

Adam

its a muliple choice question. the parthenese aren't really there i used them so it would be easier to read

A. 2x^2y^4 B. 25y^2 C. 27 D. 3x^4
___________ _______ ______ _________
(27 ) A (3x^4) B (4x^2y^4) C (25y^2) D the 25y^2 is for D.

WakeOfAshes

It is none of those for the question I answered. I dont think I understand your original formatting. hurry and take a pic and ill try and give you the answer. I gotta leave in 5 minutes.

Adam

JLRedWing13

15/2x^3y * 10y^3/9x ----> 15/9x * 10y^3/2yx^3 -----> 5/3x * 5y^2/x^3 = 25y^2/3x^4

3x+9/(x^2-4) * x^2+x-2/x^2+4x+3 -----> 3(x+3)/(x+2)(x-2) * (x+2)(x-1)/(x+3)(x+1) -----> 3/x-2 * x-1/x+1 = 3(x-1)/(x-2)(x+1) =
3x-3/x^2-x-2

WakeOfAshes

thanks jay. yeah in this case it was a + and not a /

JLRedWing13

I tried doing those problems with a + and could not figure out what the hell I was doing wrong.....it makes so much more sense now lol.

Adam

7x
_____ = _________
3y^4 12xy^6

Adam

3a+1
________
5b^2
_________
6a
______
20b^3

Adam

bump need some help with the problems above.

Adam

dipti can ride her bike 12 miles per hour in calm weather. It takes her as long to ride 75 miles with the wind as to ride 45 miles against the wind. what is the speed of the wind.

WakeOfAshes

dipti can ride her bike 12 miles per hour in calm weather. It takes her as long to ride 75 miles with the wind as to ride 45 miles against the wind. what is the speed of the wind.

Assume that X equals the speed of the wind
Assume that Y equals the times traveled on 75/45 mile trip

75 mi/Y = 12 mi/h + X mi/h
45 mi/Y = 12 mi/h - X mi/h
------------------------subtract
30 mi/Y = 2 * X mi/h

Speed of Wind = 15 mi / Y

75 mi/Y = 12 mi/h + 15 mi/Y
75 mi = Y*12 mi/h + 15
60 mi = Y * 12 mi/h
Y=60/12 hour = 5 hours.

So speed of Wind is 15 mi/Y hour = 15/5 = 3mph.

Lets Check:

75 miles/Y = 12 mph + 3 mph
75 miles = Y * 15 Miles/hour
Y = 5 hours

45 miles /Y = 12 mph - 3mph
45 miles = Y*9miles/hour
Y = 5 hours.

Thus it checks out.

So speed of Wind is 3 mph

WakeOfAshes

7x
_____ = _________
3y^4 12xy^6

3a+1
________
5b^2
_________
6a
______
20b^3

These two posts dont make any sense. If you want help, post a picture of the problem

Adam

dipti can ride her bike 12 miles per hour in calm weather. It takes her as long to ride 75 miles with the wind as to ride 45 miles against the wind. what is the speed of the wind.

Assume that X equals the speed of the wind
Assume that Y equals the times traveled on 75/45 mile trip

75 mi/Y = 12 mi/h + X mi/h
45 mi/Y = 12 mi/h - X mi/h
------------------------subtract
30 mi/Y = 2 * X mi/h

Speed of Wind = 15 mi / Y

75 mi/Y = 12 mi/h + 15 mi/Y
75 mi = Y*12 mi/h + 15
60 mi = Y * 12 mi/h
Y=60/12 hour = 5 hours.

So speed of Wind is 15 mi/Y hour = 15/5 = 3mph.

Lets Check:

75 miles/Y = 12 mph + 3 mph
75 miles = Y * 15 Miles/hour
Y = 5 hours

45 miles /Y = 12 mph - 3mph
45 miles = Y*9miles/hour
Y = 5 hours.

Thus it checks out.

So speed of Wind is 3 mph

thanks . i figured out the other 2 problems.