I can help tomorrow evening if you're still stuck. Skype's forbidden in this apartment so it will have to be by some other means if you want more than just me typing answers in here. lol
The width of a rectangle is 5 less than twice its length. If the area of the rectangle is 150 cm^2, what is the length of the diagonal?
i got 12.5 cm^2 and it says its wrong my friend Mikey is gonna help me later tonight though trying to work these problems out so theres less for him to help with
Comments
i had to factor out the (x+2)
everything i get is 0/0
are you available to maybe skype tomorrow to help me?
stickam?
im stuck on this one:
The width of a rectangle is 5 less than twice its length. If the area of the rectangle is 150 cm^2, what is the length of the diagonal?
i got 12.5 cm^2 and it says its wrong
my friend Mikey is gonna help me later tonight though
trying to work these problems out so theres less for him to help with
l*w = 150
2l - w = 5
w = 150/l
2l - 150/l = 5
2l^2 - 150 = 5l
2l^2 - 5l - 150 = 0
Quadratic formula gives l = 10
20 - 5 = 15 = w
10^2 + 15^2 = c^2
100 + 225 = c^2
c^2 = 325
c = 18.03
please please please help me with these two problems
im literally stumped
iz smaat
For the absolute value one, look at this for an example....